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Q.

In the nuclear reaction 192U238→zThA+2He4, the values of A and Z are

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a

A = 234, Z = 94

b

A = 234, Z = 90

c

A = 238, Z = 94

d

A = 238, Z = 90

answer is B.

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Detailed Solution

A = 238 – 4 = 234 and Z = 92 – 2 = 90.
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