Q.
A nuclear reactor generated power at 50% efficiency by fission of 92U235 into equal fragment of 46Pd116 with the emission of two γ -rays of 5.2 MeV each and three neutrons. The average B.E. per particle of U235 and Pd116 is 7.2 MeV and 8.2 MeV respectively. The amount of U235 consumed per hour to produce 1600Mw power is
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a
128 gm
b
1.4 kg
c
140.5 gm
d
281 gm
answer is A.
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Detailed Solution
50P100=1600MW; P=BEproduct−BEinitial t
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