Nuclei of radioactive element A are produced at rate ‘t2’ at any time t. The element A has decay constant λ. Let N be the number of nuclei of element A at any time t. At time t=to,dNdt is minimum. Then the number of nuclei of element A at time t=t0 is:
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a
2to−λto2λ2
b
to−λto2λ2
c
2to−λto2λ
d
to−λto2λ
answer is A.
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Detailed Solution
The rate of formation of radioactive nuclei is t2 Rate of decay of radioactive nuclei is λN∴dNdt=t2−λN For dNdt to be minimum; d2Ndt2=0⇒d2Ndt2=2t−λdNdt=2t−λt2−λN=0⇒N=2t−λt2λ2⇒N=2t0−λt02λ2 at t=t0