A nucleus of mass number A, originally at rest, emits an α-particle with speed v. The daughter nucleus recoils with a speed
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a
4vA-4
b
4vA+4
c
2vA+4
d
2vA-4
answer is A.
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Detailed Solution
The emission of an α-particle from the atom of an element reduces its atomic number by 2 and mass number by 4. Hence, the radioactive emission is as follows :X A Z →α-particleY A-4 Z-2 +He 4 Z (α-particle)Also from law of conservation of momentum,m x 0=myvy+mαvα =A-4vy+4v ⇒vy=4vA-4