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A nucleus with Z= 92 emits the following in a sequence: α, β-, β-, α, α, α, α, α, β-, α, β+, β+, α.The Z of the resulting nucleus is

a
74
b
76
c
78
d
82

detailed solution

Correct option is C

Zresulting nucleus=92 - 8 x 2 +4 x 1-2 x 1=78

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