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Q.

The number of atoms per unit volume in a sample of iron is 9 × 1028 atoms /m3. The magnetic moment of every iron atom is 1.5×10–23 Am2. If all dipoles are aligned in a domain due to ferromagnetic interaction, then magnetic moment and the pole strength of the rod of length 10 cm and area of cross - section 1cm2 is

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Detailed Solution

M=9 x 1028 x 1.5 x 10-23 x 10-5 =13.5 A-m2m=M2l=13.510-2 x 10=135 A-m
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The number of atoms per unit volume in a sample of iron is 9 × 1028 atoms /m3. The magnetic moment of every iron atom is 1.5×10–23 Am2. If all dipoles are aligned in a domain due to ferromagnetic interaction, then magnetic moment and the pole strength of the rod of length 10 cm and area of cross - section 1cm2 is