First slide

Projection Under uniform Acceleration

Question

A number of bullets are fired in all possible directions with the same initial velocity u. The maximum area of ground covered by bullets is

Easy

A

$π {(\frac{u^{2}}{g})}^{2}$
B

$π {(\frac{u^{2}}{2 g})}^{2}$
C

$π {(\frac{u}{g})}^{2}$
D

$π {(\frac{u}{2 g})}^{2}$

Solution

A bullet fired at angle 45° will fall maximum away, and all other bullets will fall with this bullet fired at 45°.
$R_{\max} = \frac{u^{2}}{g} Maximum area covered = π {(R_{\max})}^{2} = π (\frac{u^{2}}{g})$

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