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Questions  

A number of capacitors, each of capacitance 1μF and each one of which gets punctured a potential difference just exceeding 500 volt is applied . Then an arrangement suitable for giving a capacitor of capacitance  3 μFacross which 2000 V may be applied requires at least 

 

a
4 component capacitors
b
96 component capacitors
c
48 component capacitors
d
3 component capacitors

detailed solution

Correct option is C

to increase the potential from 500 V to 2000 V four capacitor has to be connected in series 2000500but in this process capacitance becomes 14μF  Cs=C4 so to get a capacitance of 3μF   =nx14μF  n =12so toatal no of capacitors  used as 4x12=48   ( each row four are in series and twelve such rows are in parallel)

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Similar Questions

Two capacitors C1 and C2 having capacitance 2μF and 4μF respectively are connected as shown in the figure. Initially C1 has charge 4μC and C2 is uncharged. After long time closing the switch S :


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