Questions
A number of capacitors, each of capacitance and each one of which gets punctured a potential difference just exceeding 500 volt is applied . Then an arrangement suitable for giving a capacitor of capacitance 3 across which 2000 V may be applied requires at least
detailed solution
Correct option is C
to increase the potential from 500 V to 2000 V four capacitor has to be connected in series 2000500but in this process capacitance becomes 14μF Cs=C4 so to get a capacitance of 3μF =nx14μF n =12so toatal no of capacitors used as 4x12=48 ( each row four are in series and twelve such rows are in parallel)Talk to our academic expert!
Similar Questions
Two capacitors C1 and C2 having capacitance respectively are connected as shown in the figure. Initially C1 has charge 4 and C2 is uncharged. After long time closing the switch S :
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests