First slide

Static friction

Question

A number of coins each of mass 400g are placed one over the other. The minimum horizontal force required to pull the eight coin from the top without disturbing the remaining is 10N g = 10m/s². The coefficient of friction between any two coins is

Moderate

A

$\frac{1}{3}$
B

$\frac{1}{4}$
C

$\frac{1}{6}$
D

$\frac{1}{8}$

Solution

On the eight coin upper surface normal force is 7 mg and lower surface it is 8 mg. So minimum force required
$μ (7 mg + 8 mg) = 15 μmg = 10 N$
$μ = \frac{1}{6}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App