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Q.

A  number of coins each of mass 400g are placed one over the other. The minimum horizontal force required to pull the eight coin from the top without disturbing the remaining is 10N g = 10m/s2. The coefficient of friction between any two coins is

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a

13

b

14

c

16

d

18

answer is C.

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Detailed Solution

On the eight coin upper surface normal force is 7 mg and lower surface it is 8 mg. So minimum force requiredμ(7mg+8mg)=15μmg=10Nμ=16
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A  number of coins each of mass 400g are placed one over the other. The minimum horizontal force required to pull the eight coin from the top without disturbing the remaining is 10N g = 10m/s2. The coefficient of friction between any two coins is