Number of particles is given by $$n=$$−$$Dn2$$−$$n1x2$$−$$x1crossing$$ a unit area perpendicular to $$X-axis$$ in unit time, where $$n1$$ and $$n2$$ are number of particles per unit volume for the value of x meant to $$x2$$ and $$x1$$. Find dimensions of D called as diffusion constant.

Question

Number of particles is given by $$n=$$−$$Dn2$$−$$n1x2$$−$$x1crossing$$ a unit area perpendicular to $$X-axis$$ in unit time, where $$n1$$ and $$n2$$ are number of particles per unit volume for the value of x meant to $$x2$$ and $$x1$$. Find dimensions of D called as diffusion constant.

Infinity Learn · Accepted Answer

[n]$$=$$ Number of particles crossing a unit area in unit time      $$=L$$−$$2T$$−$$1n2=n1=$$ number of particles per unit volume $$=L$$−$$3x2=x1=$$ positions ∴ $$D=$$[n]$$x2$$−$$x1n2$$−$$n1=L$$−$$2T$$−$$1$$×[L]L−$$3=L2T$$−$$1$$

Number of particles is given by $n = - D \frac{n_{2} - n_{1}}{x_{2} - x_{1}}$ crossing a unit area perpendicular to X-axis in unit time, where n₁ and n₂ are number of particles per unit volume for the value of x meant to x₂ and x₁. Find dimensions of D called as diffusion constant.

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Number of particles is given by n=−Dn2−n1x2−x1crossing a unit area perpendicular to X-axis in unit time, where n1 and n2 are number of particles per unit volume for the value of x meant to x2 and x1. Find dimensions of D called as diffusion constant.

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Number of particles is given by $n = - D \frac{n_{2} - n_{1}}{x_{2} - x_{1}}$ crossing a unit area perpendicular to X-axis in unit time, where n₁ and n₂ are number of particles per unit volume for the value of x meant to x₂ and x₁. Find dimensions of D called as diffusion constant.