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The number of photons of wavelength 540 nm emitted per second by an electric bulb of power 100 W is (taking $h = 6 \times 10^{- 34} J - \sec$ )

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100

1000

3×1020

3×1018

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Correct option is C

p=nhcλt⇒100=n×6×10−34×3×108540×10−9×1⇒n=3×1020

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The number of photons of wavelength 540 nm emitted per second by an electric bulb of power 100 W is (taking h=6×10−34J−sec)

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

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The number of photons of wavelength 540 nm emitted per second by an electric bulb of power 100 W is (taking $h = 6 \times 10^{- 34} J - \sec$ )