The number of possible natural oscillations of air column in a pipe closed at one end of length 85 cm whose frequencies lie below 1250 Hz are (Velocity of sound = 340 m s-1)
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a
4
b
5
c
7
d
6
answer is D.
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Detailed Solution
Fundamental frequency of the closed organ pipe isv=v4L Here, v=340 m s-1,L=85 cm=0.85 m∴ v=340 m s-14×0.85 m=100 HzThe natural frequencies of the closed organ pipe will bevn=(2n-1)v=v,3v,5v,7v,9v,11v,13v,… =100 Hz,300 Hz,500 Hz,700 Hz,900 Hz 1100 Hz,1300 Hz,… and so on. Thus, the natural frequencies lies below the 1250 Hz is 6.
The number of possible natural oscillations of air column in a pipe closed at one end of length 85 cm whose frequencies lie below 1250 Hz are (Velocity of sound = 340 m s-1)