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The number of turns in the coil of an AC generator is 5000 and area of the coil is 0.25m2 The coil is rotated at the rate of 100 cycles/sec in a magnetic field of 0.2wbm-2 The peak value of the emf generated is nearly.    

a
500KV
b
157KV
c
440KV
d
220KV

detailed solution

Correct option is B

flux linked linked with a coil is ϕ=nABcos ωtinduced emf e=-dϕdt=nABωSinωtmaximum emf = nABω= 5000x0.25x200πx0.2= 5000x10=15.7x104 V

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