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Q.

The number of turns of primary and secondary coils of a transformer are 5and 10 respectively and the mutual inductance of the transformer is 25 Henry.  Now the number of turns in the primary and secondary of the transformers are made 10 and 5 respectively.  The mutual inductance of the transformer (in Henry) will be

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a

6.25

b

12.5

c

25

d

50

answer is C.

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Detailed Solution

N1=5, N2=10, M=25 n1 =10, n2=5MαN1N2MM1=N1N2n1n225M1=5×1010×5M1=25H .
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