The number of turns of primary and secondary coils of a transformer are $$5and$$ $$10$$ respectively and the mutual inductance of the transformer is $$25$$ Henry. Now the number of turns in the primary and secondary of the transformers are made $$10$$ and $$5$$ respectively. The mutual inductance of the transformer (in$$ $$Henry) will be

Question

The number of turns of primary and secondary coils of a  transformer are $$5and$$ $$10$$ respectively and the mutual inductance of the  transformer is $$25$$ Henry.  Now the number  of turns in the primary and secondary of the transformers are made $$10$$ and $$5$$  respectively.  The mutual inductance of  the transformer (in$$ $$Henry) will be

Infinity Learn · Accepted Answer

$$N1=5$$, $$N2=10$$, $$M=25$$ $$n1$$ $$=10$$, $$n2=5M$$α$$N1N2MM1=N1N2n1n225M1=5$$×$$1010$$×$$5M1=25H$$ .

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