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Q.

The number of turns of primary and secondary coils of a transformer are 5 and 10 respectively and the mutual inductance of the transformer is 25 henry. Now the number of turns in the primary and secondary of the transformer are made 10 and 5 respectively. The mutual inductance of the transformer in henry will be

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a

6.25

b

12.5

c

25

d

50

answer is C.

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Detailed Solution

M=μ0N1N2Al M1M2=5×1010×5 M2=M1=25H
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