A number of water droplets each of radius coalesce to form a droplet of radius fl. The rise in temperature d θ is
(2T/rJ)
(3T/rJ)
3TJ1r−1R
3TJ1r+1R
Let R be the radius of a single drop. Then43πR3=n×43πr3 or R3=nr3 Decrease in surface area =4πr2n−4πR2 =4πnr2−R2=4πnr3r−R2 =4πR3r−R2=4πR31r−1R Heat produced =4πR3TJ1r−1R Rise in temperature d0 is given by 43πR3×1×dθ=4πR3TJ1r−1R dθ=3TJ1r−1R