First slide

Thermal expansion

Question

The numerical value of coefficient of linear expansion is independent of units of
(a) length (b) temperature
(c) area (d) mass

Easy

A

only (a) is correct
B

(a) & (b) are correct
C

(a), (b) & (c) are correct
D

(a), (c) & (d) are correct

Solution

$\large \alpha \, = \,\frac{{\Delta l}}{{l.\Delta t}}$

Now
$\large \left( {\frac{{\Delta l}}{l}} \right)$
is fractional change in length, which is dimensionless. So $α$ depends only upon the unit of temperature.

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