A nylon rope 2 cm in diameter has a breaking strength of 1.5 x 105 N. The breaking strength of a similar rope 1 cm in diameter is
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a
0.375×105N
b
2×105N
c
6×105N
d
9×104N
answer is A.
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Detailed Solution
Breaking strength = Breaking stress ×πD24Breaking stress is unchanged.D is halved. So, breaking strength becomes one-fourth, i.e.,14×1.5×105N or 0.375×105N