Ray optics

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Question

An object 2.5 cm high is placed at a distance of 10 cm from a concave mirror of radius of curvature 30 cm. The size of the image is

Solution

$R = - 30 cm \Rightarrow f = - 15 cm, O = + 2.5 cm, u = - 10 cm By mirror formula \frac{1}{- 15} = \frac{1}{v} + \frac{1}{(- 10)} \Rightarrow v = 30 cm Also \frac{I}{O} = \frac{v}{u} \Rightarrow \frac{1}{(+ 2.5)} = \frac{30}{(- 10)} \Rightarrow I = + 7.5 cm$

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