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Q.

An object is cooled from 750C to 650C in 2 minutes in a room at 300C. The time taken to cool another identical object from 550C to 450C in the same room in minutes is

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Detailed Solution

Newton’s law for cooling.Rate of decrease of temperature  temperature difference between object and surrounding.75−652=c(70−30)55−45t=c(50−30)∴ t=4 min.
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