First slide

Release from certain height

Question

An object is dropped from the top of a tower. It travels a distance 'x' in the first second of its motion and a distance '7x' in the last second. Height of the tower is
(take g= 10 m/s²)

Easy

A

60 m
B

70 m
C

80 m
D

90 m

Solution

$x = \frac{1}{2} g {(1)}^{2} and 7 x = 0 + \frac{g}{2} (2 T - 1)$
T = 4s
Height of tower $= \frac{1}{2} {gT}^{2} = \frac{1}{2} (10) {(4)}^{2} = 80 m$

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