First slide

Simple hormonic motion

Question

An object executing SHM has an acceleration of 0.2m/s² at a distance of 0.05m from the mean position. Calculate the period of SHM.

Easy

A

5.764sec
B

4.654sec
C

3.142sec
D

2.764sec

Solution

a = 0.2m/sec², T = ?
y = 0.05m
$\large a\, = \,{\omega ^2}y\, \Rightarrow \,{\omega ^2}\, = \,\frac{{0.2}}{{0.05}}\, = \,\frac{{20}}{5} = 4\, \Rightarrow \,\omega \, = \,2rad/s$
$\large \frac{{2\pi }}{T}\, = \,2\, \Rightarrow \,\pi \, = \,T\,\,\,\,\,\,\,\,\,\,\,\,\,\,T\, = \,3.142\sec$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App