Questions
An object having a velocity 4 m/s is accelerated at the rate of 1.2 m/s 2 for 5 sec. find the distance covered during the period of acceleration.
detailed solution
Correct option is B
given, intitial velocity= u=4m/sacceleration=a=1.2m/s2time=t=5sec equation of motion Distance =S=ut+12at2S=(4×5)+12(1.2)52S=35mTalk to our academic expert!
Similar Questions
A particle is moving along the x-axis whose acceleration is given by , where x is the location of the particle. At t = 0, the particle is at rest at x = 4/3 m. The distance travelled by the particle in 5 s is
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