Questions
An object is kept at a distance of 16 cm from a thin lens and the image formed is real. If the object is kept at a distance of 6 cm from the same lens the image formed is virtual. If the size of the images formed are equal, the focal length of the lens will be
detailed solution
Correct option is D
Only convex lens can form a real well as virtual image. So, the given lens is a convex lens. Let f is the focal length of the lens and n the magnitude of magnification.In the first case u,hen the image is realu = -16 cmv = +16 nSo, applying 1v−1u=1f116n+116=1for 1+1n=16f . . . . 1in the second case when image is virtualu=−6cmv=−6nf=+f∴1−6n+16=1f∴1−1n=6f . . . . 2Adding 1 and 2 we get2=22f or f=11cmTalk to our academic expert!
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