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Q.

An object kept in a large room having air temperature of 25°C takes 12 minutes to cool from 80°C to 70°C.The time taken to cool for the same object from 70°C to 60°C would be nearly,

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a

15 min

b

10 min

c

12 min

d

20 min

answer is A.

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Detailed Solution

Using average method in Newton's law of coolingT1-T2t=KT1+T22-T0 (80-70)12=K(75-25) … (70-60)t'=K(65-25) …(i)Divide eq. (i) by (ii)t'=12×54=15 min
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