Q.
An object kept in a large room having air temperature of 25°C takes 12 minutes to cool from 80°C to 70°C.The time taken to cool for the same object from 70°C to 60°C would be nearly,
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a
15 min
b
10 min
c
12 min
d
20 min
answer is A.
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Detailed Solution
Using average method in Newton's law of coolingT1-T2t=KT1+T22-T0 (80-70)12=K(75-25) … (70-60)t'=K(65-25) …(i)Divide eq. (i) by (ii)t'=12×54=15 min
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