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Q.

An object of m kg with speed of v m/s strikes a wall at an angle θ and rebounds at the same speed and same angle. The magnitude of the change in momentum of the object will be

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a

2mvcos⁡θ

b

2mvsin⁡θ

c

0

d

2mv

answer is A.

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Detailed Solution

P→1=mvsin⁡θi^−mvcos⁡θj^ and P→2=mvsin⁡θi^+mvcos⁡θj^ So change in momentum ΔP→=P→2−P→1=2mvcos⁡θj^,|ΔP→|=2mvcos⁡θ
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An object of m kg with speed of v m/s strikes a wall at an angle θ and rebounds at the same speed and same angle. The magnitude of the change in momentum of the object will be