An object of m kg with speed of v m/s strikes a wall at an angle θ and rebounds at the same speed and same angle. The magnitude of the change in momentum of the object will be
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a
2mvcosθ
b
2mvsinθ
c
0
d
2mv
answer is A.
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Detailed Solution
P→1=mvsinθi^−mvcosθj^ and P→2=mvsinθi^+mvcosθj^ So change in momentum ΔP→=P→2−P→1=2mvcosθj^,|ΔP→|=2mvcosθ
An object of m kg with speed of v m/s strikes a wall at an angle θ and rebounds at the same speed and same angle. The magnitude of the change in momentum of the object will be