Questions
An object of m kg with speed of v m/s strikes a wall at an angle and rebounds at the same speed and same angle. The magnitude of the change in momentum of the object will be
detailed solution
Correct option is A
P→1 = mv sinθi^−mvcosθj^ and P2→ = mvsinθi^+mvcosθj^So change in momentumΔP→ = P2→ −P1→ = 2 mv cosθj^, |ΔP→| = 2mv cosθTalk to our academic expert!
Similar Questions
Statement I : The familiar equation mg = R for a body on a table is true only if the body is in equilibrium.
Statement II : The equality of mg and R has no connection with the third law.
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