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An object of m kg with speed of v m/s strikes a wall at an angle θ and rebounds at the same speed and same angle. The magnitude of the change in momentum of the object will be

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a

2mv cosθ

b

2mv sinθ

c

0

d

2mv

answer is A.

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Detailed Solution

P→1 = mv sinθi^−mvcosθj^ and P2→ = mvsinθi^+mvcosθj^So change in momentumΔP→ = P2→ −P1→ = 2 mv cosθj^, |ΔP→| = 2mv cosθ

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