An object of mass 0.2 kg executes simple harmonic motion along the x-axis with a frequency of 25/π Hz. At the position x = 0.04 m, the object has a kinetic energy of 0.5 J and potential energy of 0.4 J. The amplitude of oscillation is

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0.05 m

0.06 m

0.01 m

none of these

answer is B.

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Detailed Solution

E=12mω2A2=12m(2πf)2A2 A=12πf2Em Putting E = K+U, we get A=12π(25/π)2×(0.5+0.4)0.2=0.06m

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