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Question

An object of mass 5kg falls from rest through a vertical distance 20m and attains a velocity of 10m/s work is done by the resistance of air on the object is $- 250 \times n J$ then value of $n$ is

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Solution

$W_{a i r} + W_{g} = Δ K$
$W_{a i r} + m g h = \frac{1}{2} m u^{2}$
$W_{a i r} = \frac{1}{2} (5) 10^{2} - 5 \times 10 \times 20$
$W_{a i r} = - 750 J = - 250 \times 3 J$

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