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An object of mass 5kg falls from rest through a vertical distance 20m and attains a velocity of 10m/s work is done by the resistance of air on the object is −250×nJ then value of n is

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answer is 3.

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Detailed Solution

Wair+Wg=ΔK Wair+mgh=12mu2Wair=12(5)102−5×10×20Wair=−750 J=-250×3J

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