First slide

Work done by Diff type of forces

Question

An object of mass 6 kg is moved with uniform speed of 8 m/s for 8 sec on a surface. Coefficient of friction between the body and the surface is 0.6, work done for the given motion of the body is : (take g = 10 m/s²)

Easy

A

2212 J
B

2304 J
C

1192 J
D

3222 J

Solution

Work done = $(μmg) d$ (0.6) (6) ( 10) (8 x 8) = 2304 J

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