Q.

An object of mass 4 kg is moving along X-axis and its potential energy as a function of x can be expressed as U(x) = 4 (1- cos 2x) joule then time period for small oscillations is:

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya

a

π2 sec

b

π4 sec

c

π sec

d

3π2 sec

answer is C.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

F=-dUdx=-4×2 sin 2x For small oscillations, sin 2x≈2x                              F=-16x⇒a=Fm=-4x                               ω2=4⇒T=π sec
Watch 3-min video & get full concept clarity
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon
An object of mass 4 kg is moving along X-axis and its potential energy as a function of x can be expressed as U(x) = 4 (1- cos 2x) joule then time period for small oscillations is: