First slide

Work done by Diff type of forces

Question

An object of mass 4 kg is moving along X-axis such that its position x varies with time t as x² = 16t³, with t in meter and r in sec. Work done as a function of time can be shown as :

Moderate

A
B
C
D

Solution

$x^{2} = 16 t^{3} \Rightarrow x = 4 t^{3 / 2} \Rightarrow v = 6 t^{1 / 2} \Rightarrow v^{2} = 36 t$
But work done - change in KE. So work done $\propto$ t

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