First slide

Second law

Question

An object of mass 5 kg is moving with a constant velocity of 10 m s^-1. A constant force acts on it opposite to its velocity 4 seconds and gives it a velocity of 2 m s^-1 in the opposite direction. The acceleration produced by the force is

Easy

A

2 m s^-2
B

3 m s^-2
C

4 m s^-2
D

5 m s^-2

Solution

Using V = u + at, we can write
$- 2 = 10 + a \times 4 \Rightarrow a = - 3 m / s^{2}$ (Retardation)
$∴ Acceleration produced = 3 m / s^{2}$

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