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Q.

An object of mass m is projected with a momentum ρ at such an angle that its maximum height is 1/4th ofits horizontal range. Its minimum kinetic energy in its path will be

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a

p28m

b

p24m

c

3p24m

d

p2m

answer is B.

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Detailed Solution

It is given that,  H=R4∴  u2sin2θ2g=2u2sinθcosθ4g or tanθ=1⇒θ=450At highest point, momentum will remain  p2∴  K=(p/2)22m=p24m
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