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Questions  

An object of mass m is projected with a momentum ρ at such an angle that its maximum height is 1/4th of
its horizontal range. Its minimum kinetic energy in its path will be

a
p28m
b
p24m
c
3p24m
d
p2m

detailed solution

Correct option is B

It is given that,  H=R4∴  u2sin2θ2g=2u2sinθcosθ4g or tanθ=1⇒θ=450At highest point, momentum will remain  p2∴  K=(p/2)22m=p24m

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