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An object of mass 'm' is projected with a velocity 'u' at an angle 45° with the horizontal. When the object is at maximum height, its angular momentum about the point of projection is

a
mu2g
b
mu22g
c
mu342g
d
muu2g

detailed solution

Correct option is C

Angular momentum =(mucos⁡θ)Hmax=(mucos⁡θ)u2sin2⁡θ2g

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