An object moves along a straight line path from P to Q under the action of a force (4i^−3j^+3k^) N. If the coordinates of P and Q, in meters, are (3,3,−1) and (2,−1,4) respectively, then the work done by the force is

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+ 23 J

−23 J

1015 J

35(4i^−3j^+2k^)J

answer is A.

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Detailed Solution

(PQ→)=r→=(2−3)i^+(−1−3)j^+(4+1)k^ =−1i^−4j^+5k^ Work done =F→.r→ =(4i^−3j^+3k^).(−1i^−4j^+5k^) =−4+12+15=23 J

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