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Q.

An object, moving with a speed of 6.25 m/s, is declerated at a rate given by, dvdt=−2.5v where v is the instantaneous speed. The time taken by theobject, to come to rest would be

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a

2 s

b

4 s

c

8 s

d

1 s

answer is A.

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Detailed Solution

Given ;dvdt=2.5v⇒ dvv=−2.5dt⇒ ∫6.260 v−1/2dv=−2.5∫0t dt⇒ −2.5[t]0t=2v1/26.250t = 2 s
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