Questions
An object, moving with a speed of 6.25 m/s, is declerated at a rate given by, where v is the instantaneous speed. The time taken by the
object, to come to rest would be
detailed solution
Correct option is A
Given ;dvdt=2.5v⇒ dvv=−2.5dt⇒ ∫6.260 v−1/2dv=−2.5∫0t dt⇒ −2.5[t]0t=2v1/26.250t = 2 sTalk to our academic expert!
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The average velocity of a body moving with uniform acceleration after travelling a distance of 3.06 m is 0.34 ms-1. If the change in velocity of the body is 0.18 ms-1 during this time, its uniform acceleration is
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