An object is moving with velocity 10 ms-1. A constant force acts for 4 s on the object and gives it a speed of 2 ms-1 in opposite direction. The acceleration produced is

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3ms-2

-3ms-2

6ms-2

-6ms-2

answer is B.

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Detailed Solution

Given, v = - 2 ms-1 (opposite direction),t = 4 s and u =10 ms-1∴ v = u + at or - 2 =10 + 4a or a = - 3 ms-2

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