First slide

Ray optics

Question

An object is placed at a distance of 40cm from a concave mirror of focal length 15cm. If the object is displaced through a distance of 20cm towards the mirror, the displacement of the image will be

Moderate

A

30cm away from the mirror
B

36cm away from the mirror
C

36cm towards the mirror
D

30cm towards the mirror

Solution

$\Rightarrow v_{1} = \frac{u_{1} f}{u_{1} - f} = \frac{40 (15)}{40 - 15} = 24 cm \to 1 \Rightarrow v_{2} = \frac{u_{2} f}{u_{2} - f} = \frac{60 (15)}{60 - 15} = 60 cm \to 2 ∆ v = v_{2} - v_{1} = 60 - 24 = 36 cm$
away from the mirror

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