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Q.

An object is placed at a distance of 12 cm from a converging lens on its principal axis and a virtual image of certain size is formed. Now the lens is moved 4 cm away from the object and a real image of the same size as that of the (previous) virtual image is formed. The focal length in cm of the lens is:

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a

14

b

16

c

18

d

20

answer is A.

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Detailed Solution

1v−1u=1f ; uv=1+ufm=vu=fu+f;f−12+f=−f−16+f (∵m is same in both the cases ).f=14cm.
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