Questions
An object is placed at a distance of 12 cm from a converging lens on its principal axis and a virtual image of certain size is formed. Now the lens is moved 4 cm away from the object and a real image of the same size as that of the (previous) virtual image is formed. The focal length in cm of the lens is:
detailed solution
Correct option is A
1v−1u=1f ; uv=1+ufm=vu=fu+f;f−12+f=−f−16+f (∵m is same in both the cases ).f=14cm.Talk to our academic expert!
Similar Questions
In the diagram shown, the lens is moving towards the object with a velocity V m/s and the object is also moving towards the lens with the same speed. What is speed of the image with respect to earth when the object is at a distance 2f from the lens?
(f is the focal length):
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