An object is placed at a distance of f2 from a convex lens. The image will be
At one of the foci, virtual and double its size
At 3f2, real and inverted
At 2f, virtual and erect
None of these
1f=1v−1u Given u=−f2 ⇒1f=1v+1f/2⇒1v=1f−2f ⇒1v=−1f and m=vu=ff/2=2 So virtual at the focus and of double size