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Q.

An object is placed infront of a concave mirror of focal length 'f'. A virtual image is formed with a magnification of 2. To obtain a real image of same magnification, the object has to moved by a distance

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a

f

b

f/2

c

3f/2

d

2f/3

answer is A.

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Detailed Solution

1f=1v+1u ; v1=-2u, v2=2u 1f=1v1+1u1, 1f=1v2+1u2Distance moved by the object = u1- u2= f
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