An object is placed infront of a concave mirror of focal length 'f'. A virtual image is formed with a magnification of 2. To obtain a real image of same magnification, the object has to moved by a distance
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a
f
b
f/2
c
3f/2
d
2f/3
answer is A.
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Detailed Solution
1f=1v+1u ; v1=-2u, v2=2u 1f=1v1+1u1, 1f=1v2+1u2Distance moved by the object = u1- u2= f
An object is placed infront of a concave mirror of focal length 'f'. A virtual image is formed with a magnification of 2. To obtain a real image of same magnification, the object has to moved by a distance