Q.

An object is placed on the principal axis of a concave mirror at a distance of 1.5 f (f is the focal length). The image will be at,

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a

3 f

b

-3 f

c

1.5 f

d

-1.5 f

answer is B.

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Detailed Solution

By mirror formula1v+1u=1f1v−13f2=1−f1v−23f=−1f1v=−1f+23f1v=−3+23fv=−3f
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