First slide
Kinetic friction
Question

An object is placed on the surface of a smooth inclined plane of inclination θ. It takes time t, to reach the bottom. If the same object is allowed to slide down a rough inclined plane of inclination q, it takes time n t to reach the bottom where n is a number greater than one. The coefficient of friction μ is given by

Moderate
Solution

For smooth inclined plane, acceleration = g sin q

For rough inclined plane, acceleration =gsinθμgcosθ

Let l be the length of inclined plane, then l=12(gsinθ)t2  …(1)

also l=12(gsinθμgcosθ)(nt)2   …(2)

 12(gsinθ)t2=12(gsinθμgcosθ)(nt)2

Solving, we get

μ=tanθ11n2.

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