An object is projected horizontally from a top of the tower of height h. The line joining the point of projection and point of striking on the ground makes an angle 450 with ground,Then with what velocity the object strikes the ground
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a
gh2
b
9gh2
c
7gh2
d
5gh2
answer is A.
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Detailed Solution
Tanθ=hR,R=u2 h g and θ= 450 Therefore h = u2hg ⇒u = gh2