An object is projected with a velocity of $$20$$ $$ms-1$$ making an angle of $$450$$ with horizontal. The equation for trajectory is h $$=$$ Ax $$-$$ $$Bx2$$ , where h is height, x is horizontal distance, A and B are constants. The ratio A : B is (Take$$, g $$=$$ $$10$$ $$ms-2)

Question

An object is projected with a velocity of $$20$$ $$ms-1$$ making an angle of $$450$$ with horizontal. The equation for trajectory is h $$=$$ Ax $$-$$ $$Bx2$$ , where h is height, x is horizontal distance, A and B are constants. The ratio A : B is (Take$$, g $$=$$ $$10$$ $$ms-2)

Infinity Learn · Accepted Answer

Standard equation of projectile motion,$$y=xtan$$θ$$-gx22u2cos2$$θComparing with given equation,$$A=$$$$tan$$θ and $$B=g2u2cos2$$θ So, $$AB=$$$$tan$$θ×$$2u2cos2$$θ$$g=40$$:$$1$$ As θ$$=45$$°,$$u=20$$ $$ms-1$$,$$g=10$$ $$ms-2$$

An object is projected with a velocity of 20 $m s^{- 1}$ making an angle of 45⁰ with horizontal. The equation for trajectory is h = Ax $-$ Bx² , where h is height, x is horizontal distance, A and B are constants. The ratio A : B is (Take, g = 10 $m s^{- 2}$ )

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An object is projected with a velocity of 20 ms-1 making an angle of 450 with horizontal. The equation for trajectory is h = Ax - Bx2 , where h is height, x is horizontal distance, A and B are constants. The ratio A : B is (Take, g = 10 ms-2)

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Ready to Test Your Skills?

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An object is projected with a velocity of 20 $m s^{- 1}$ making an angle of 45⁰ with horizontal. The equation for trajectory is h = Ax $-$ Bx² , where h is height, x is horizontal distance, A and B are constants. The ratio A : B is (Take, g = 10 $m s^{- 2}$ )