An object of radius R and mass M is rolling horizontally without slipping with speed v. It then rolls up the hill to a maximum height is h=3v24g. The moment of inertia of the object is (g = acceleration due to gravity) :
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a
25MR2
b
MR22
c
MR2
d
32MR2
answer is B.
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Detailed Solution
Loss in KE = Gain in PE12mv21+K2R2=mgHv221+K2R2=g3e24gK2R2=12I=MK2=MR22