First slide

Vertical projection from ground

Question

An object reaches a maximum vertical height of 23.0 m when thrown vertically upward on the earth. How high would it travel on the moon where the acceleration due to gravity is about one sixth that on the earth ? Assume that initial velocity is the same.

Moderate

A

138m
B

100m
C

10m
D

69m

Solution

Maximum height H = $\frac{u^{2}}{2 g}$
$\Rightarrow H \infty \frac{1}{g} \Rightarrow \frac{H^{"}}{H} = \frac{g}{g^{"}} \Rightarrow H^{"} = H \frac{g}{g^{"}} = 23 \times 6 m = 138 m$

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