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Q.

An observer moves towards a stationary source of sound with a speed 1/5th of the speed of sound. The wavelength and frequency of the source emitted are λ and f respectively. The apparent frequency and wavelength recorded by the observer are respectively

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a

1.2f, λ

b

f, 1.2λ

c

0.8f, 0.8λ

d

1.2f, 1.2λ

answer is A.

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Detailed Solution

n'=v+v0v.n=v+v5v.f=65f=1.2f and since the source is stationary, so wave length remains unchanged for observer.
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