An observer moves towards a stationary source of sound with a speed 1/5th of the speed of sound. The wavelength and frequency of the source emitted are λ and f , respectively. The apparent frequency and wavelength recorded by the observer are respectively.

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f,1.2λ

0.8f,0.8λ

1.2f,0.83λ

1.2f,λ

answer is D.

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Detailed Solution

Motion of the observer does not change the wavelength.Apparent frequency n1=v+vovf

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